An electric dipole is placed in a uniform electric field. The net electric force on the dipole
(a) is always zero
(b) depends on the orientation of the dipole
(c) can never be zero
(d) depends on the strength of the dipole.
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An electric dipole with dipole moment 4 × 10^−9 C m is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 10^4 N C^−1.
Electric dipole moment, p = 4 × 10−9 C m Angle made by p with a uniform electric field, θ = 30° Electric field, E = 5 × 104 N C−1 Torque acting...
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A electric dipole is placed at an angle of 30º to a nonuniform electric field.
(d) In a nonuniform electric field, the dipole will experience a torque as well as a translational force.
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A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region.
(c) : Magnetic field applied parallel to motion of electron exerts no force on it as θ = 0 and force = Bevsinθ = zero Electric field opposes motion of electron which...
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An electric dipole is placed in an electric field generated by a point charge.
(d) The torque on the dipole due to the field may be zero.
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A proton and an electron are placed in a uniform electric field.
(b) The magnitudes of the forces will be equal.
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A particle moves in a region having a uniform magnetic field and a parallel, uniform electric field.
(d) a helix with nonuniform pitch.
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A conducting loop is placed in a uniform magnetic field with its plane perpendicular to the field.
The correct answer is (c) (d) (c) it is rotated about a diameter (d) it is deformed.
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In which orientation, a dipole placed in a uniform electric fields is in (i) stable, (ii) unstable equilibrium?
(i) In stable equilibrium the dipole moment is parallel to the direction of electric field (i.e., θ = 0). (ii) In unstable equilibrium P.E. is maximum, so θ = π so...
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Define dipole moment of an electric dipole. Is it a scalar or a vector?
Dipole moment of an electric dipole is the product of either of charge and the length of dipole. It is a vector quantity. vector P = q(2vector a)
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A sample of HCl gas is placed in an electric field of 2.5 x 10^4 N/C. The dipole moment of each HCl
E = 2.5 × 104 P = 3.4 × 10–30 τ = PE sinθ = P × E × 1 = 3.4 × 10–30 × 2.5 × 104 = 8.5 × 10–26
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