Find the surface energy of water kept in a cylindrical vessel of radius 6.0 cm. Surface tension of water = 0.075 J/m2.
Here, h = 25 cm, 2πr = 132 cm. 2πr = 132 ⇒ 2 × 22/ 7 × r = 132 ⇒ r = 132x 7/ 2 x 22 cm = 21...
1 Answers 1 viewsHere, h = 10 m (i) Inner curved surface area = Total cost / Cost of painting per m2 = 2200 / 20 m2 = 110 m2 Ans. (ii) We have, 2πrh =...
1 Answers 2 viewsAir around us gets heated from sunlight. This warm air provides heat for evaporation of water kept in the shade.
1 Answers 1 viewsThe correct answer is (d) 24πr2S. Explanation: The surface tension S is equal to surface energy per unit area, S = U/A →U = SA The total area of the soap bubble =2*4πr² =8πr² The...
1 Answers 1 viewsHow it comes cot r = 3/4 ?
1 Answers 1 viewsLength of the thread, L = 5.0 cm =0.05 m The surface tension of the water, S = 0.076 N/m Hence the force of surface tension on one side of the thread...
1 Answers 1 viewsThanks for the answer I was confused what to take area thanks
1 Answers 1 viewsThe correct answer is (C) 2.25.
1 Answers 1 views