Find the surface energy of water kept in a cylindrical vessel of radius 6.0 cm. Surface tension of water = 0.075 J/m^2.

Here, h = 25 cm, 2πr = 132 cm. 2πr = 132  ⇒ 2 × 22/ 7 × r = 132  ⇒ r = 132x 7/ 2 x 22 cm = 21...

Here, h = 10 m  (i) Inner curved surface area = Total cost / Cost of painting per m2  = 2200 / 20 m2 = 110 m2 Ans.  (ii) We have, 2πrh =...

Air around us gets heated from sunlight. This warm air provides heat for evaporation of water kept in the shade.

The correct answer is (d) 24πr2S. Explanation:  The surface tension S is equal to surface energy per unit area, S = U/A  →U = SA  The total area of the soap bubble =2*4πr² =8πr²  The...

How  it comes cot r = 3/4 ?

Length of the thread, L = 5.0 cm =0.05 m  The surface tension of the water, S = 0.076 N/m  Hence the force of surface tension on one side of the thread...

The correct answer is (C)  2.25.