The lower end of a capillary tube is immersed in mercury. The level of mercury in the tube is found to be 2 cm below the outer level. If the same tube is immersed in water, upto what height will the water rise in the capillary ?
Rise/depression = 2S.cosθ/rρg
For mercury -0.02 = 2S'.cosθ/rρ'g ------- (i)
For water rise, h = 2S.cos0°/rρg ------- (ii)
Dividing (ii) by (i)
h/0.02 = -Sρ'/(S'*cosθ*ρ)
→h = -0.02*Sρ'/(1000S'.cosθ)
S' =7.5 x 10⁻² N/m. S = 0.465 N/m
ρ' = 13600 kg/m³
θ = 140°
So, h = -0.02*7.5x10⁻²*13600/(1000*0.465*cos140°)
→h = 0.0573 m = 5.73 cm