The lower end of a capillary tube is immersed in mercury. The level of mercury in the tube is found to be 2 cm below the outer level. If the same tube is immersed in water, upto what height will the water rise in the capillary ?


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Rise/depression = 2S.cosθ/rρg 

For mercury -0.02 = 2S'.cosθ/rρ'g  ------- (i) 

For water rise, h = 2S.cos0°/rρg     ------- (ii) 

Dividing (ii) by (i) 

h/0.02 = -Sρ'/(S'*cosθ*ρ) 

→h = -0.02*Sρ'/(1000S'.cosθ) 

S' =7.5 x 10⁻²  N/m. S = 0.465 N/m 

ρ' = 13600 kg/m³ 

θ = 140° 

So, h = -0.02*7.5x10⁻²*13600/(1000*0.465*cos140°) 

→h = 0.0573 m = 5.73 cm

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