Water rises in a vertical capillary tube upto a length of 10 cm. If the tube is inclined at 45°, the length of water risen in the tube will be

(a) 10 cm

(b) 10√2 cm

(c) 10/√2 cm

(d) none of these.


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The correct answer is (b) 10√2 cm

Explanation: 

When the tube is inclined, the vertical rise remains the same. So the water in the inclined tube rises to 10*sec45° =10√2 cm.