A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen
(a) straight line
(b) parabola
(c) hyperbola
(d) circle
(a) In a single slit diffraction experiment, if the width of the slit is made double the original width, then the size of the central diffraction band reduces to half...
1 Answers 1 viewsThe correct answer is (b) IO/4 EXPLANATION: As in the previous explanation the maximum intensity I₀ = (√I₁ + √I₂)². Here given that I₁ = I₂ = I (say). →I₀ = 4 I -------...
1 Answers 1 views(c) remain same EXPLANATION: The fringe width is given as w = Dλ/d where D = distance of the screen from the slits d = distance of slits. The wavelength λ remains the same...
1 Answers 1 views(a) the fringe width will decrease EXPLANATION: As the wavelength of light in water will decrease, hence the fringe width will decrease because the fringe width is proportional to the wavelength.
1 Answers 1 views(b) consecutive fringes will come closer EXPLANATION: The options (a), (c) and (d) are related to the intensity changes. Since the intensity of light incident on the slits is not changed...
1 Answers 1 viewsThe correct answer is (3) Straight line Note: If instead of Young's double slit experiment, young’s double hole experiment was given shape would have been hyperbola.
1 Answers 1 views(i) Angular separation βθ = β/D = λ/d It is independent of D; therefore, angular separation remains unchanged if screen is moved away from the slits. But the actual separation between fringes β = λD/d increases, so visibility...
1 Answers 1 viewsAngular separation between fringes βθ = λ/d where λ = wavelength, d = separation between coherent sources, βθ is independent of distance between the slits and screen; so angular separation (βθ) will remain unchanged.
1 Answers 1 viewsIn single slit diffraction experiment fringe width is β = 2λD/d If d is doubled, the width of central maxima is halved. Thus size of central maxima is reduced to half. Intensity...
1 Answers 1 viewsThe fringe width is β = λD/d If D (distance between slits and screen) is doubled, then fringe width will be doubled.
1 Answers 1 views