A 100 W electric bulb is lighted for 3h daily and four 60 W electric bulbs are lighted for 2h daily. Calculate the units of energy consumed in a month of 30 days.
P = 100W = 0.1 W
t = 3 h
Energy consumed by 100 W bulb per day = 0.1×3 = 0.3 kWh
Energy consumed per day by four 60 W bulbs = 0.06×4×2 = 0.48 kWh
Total Energy consumed in a month of 30 days = (0.3 + 0.48) kWh × 30
= 0.78 × 30
= 23.40 units
3 bulbs are to be selected at random from the lot. Each bulb in the lot is tested and classified as defective (D) or non-defective (N).
The sample space of this...
(i) Total numbers of bulbs = 20
Numbers of defective bulbs = 4
Probability of getting a defective bulb = 4/20 = 1/5
(ii) One non defective bulb is drawn in (i) then...
Since each light can be switched on independently,
there are two options for each bulb (on or off)
∴Total no. of ways the bulbs can be operated= 210
This includes all the bulbs are...
3 bulbs are to be selected at random from the lot. Each bulb in the lot is tested and classified as defective (D) or non-defective (N).
The sample space of this...
The resistance of the bulb is given by R=(V2/P). So, the resistance of 60 W bulb is more than the resistance of 100 W bulb. When they are connected in...
There are 6 defective bulbs out of 24 bulbs
Favourable number of elementary events = 24 – 6 = 18
∴ Probability that the bulb is not defective =18/24=3/4
When the selected bulb...