The resistance of the bulb is given by R=(V2/P). So, the resistance of 60 W bulb is more than the resistance of 100 W bulb. When they are connected in series, the current through both bulbs is same. Hence 60 W bulb will be more brighter because P = I2R.
(i) Total numbers of bulbs = 20
Numbers of defective bulbs = 4
Probability of getting a defective bulb = 4/20 = 1/5
(ii) One non defective bulb is drawn in (i) then...
Resistance of the resistor, R = 100 Ω
Supply voltage, V = 220 V
Frequency, ν = 50 Hz
(a) The rms value of current in the circuit is given as
l =V/R =220/100=2.20A
(b)...
The resistance of the bulb is defined as R =V2/P So the resistance of 50W bulb is double than the resistance of 100W bulb. When they are connected in series...
