One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:

(i) T, (ii) T-(mv2)/l (iii) T+(mv2)/l (iv) 0

T is the tension in the string. [Choose the correct alternative].


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(i) T
When a particle connected to a string revolves in a circular path around acentre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension T, i.e.,
= =(mv2)/l

Where F is the net force acting on the particle.

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(i) T 

When a particle connected to a string revolves in a circular path around a centre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension T, i.e.,

F = T = mv2/l

Where F is the net force acting on the particle.

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1. The centripetal force necessary for the particle to move in a circular path is provided by the tension in the string. Hence net force on the particle is nothing but tension T in the string.

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Correct option is (A) T

The particle is performing circular motion and is constantly accelerated. Hence, it is under the action of external force. As the motion here is confined to horizontal plane, net force on the particle is T.

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