At what speed a body of mass 1 kg will have a kinetic energy of 1 J
it is a numerical
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The kinetic energy of an object of mass, m moving with a velocity of 5 m s −1 is 25 J. What will be its kinetic energy
Expression for kinetic energy Ek= ½ mv2 m = Mass of object v = Velocity of the object in ms−1 Given that kinetic energy, Ek=25J (i) If the velocity of an object is doubled, then...
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(a) Define kinetic energy of an object. Can kinetic energy of an object be negative? Give reason.
(a) Kinetic energy of an object is defined as the energy possessed by a body by virtue of its motion. It is given by, K.E = 1/2 mv2 No, the kinetic energy...
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Two masses m and 2 m are dropped from heights h and 2h. On reaching the ground, which body will have a greater kinetic energy and why?
K.E. of first mass, m = P.E. lost by mass m = mgh K.E. of second mass, 2 m = P.E. lost by mass 2 m = 2 m × g ×...
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A horse of mass 210 kg and a dog of mass 25 kg are running at the same speed. Which of the two possesses more kinetic energy? How?
Kinetic energy, K.E. = 1/ 2 mv2 If the velocity is constant, Kinetic energy is directly proportional to mass. So as mass increases, kinetic energy also increases. Here, mass of horse...
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What will cause greater change in kinetic energy of a body? Changing its mass or changing its velocity.
As K .E = 1/2 mv2 therefore, K . E ∝ m K . E ∝ v2 Therefore, the change in velocity of a body will cause greater change in kinetic energy.
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In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system.
True In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system. This is because in such collisions, there is always a loss...
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A body A of mass M while falling vertically downwards under gravity breaks into two parts; a body B of mass (1/3)M and body C of mass (2/3)M.
(d) : The centre of mass of bodies B and C taken together does not shift as no external force is applied horizontally.
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The kinetic energy needed to project a body of mass m from the earth's surface to infinity is.
(c) mgR. EXPLANATION: The kinetic energy should be equal to the gravitational potential energy K=U = GMm/R. Since g = GM/R² →GM =gR² Hence, K = gR²*m/R =mgR
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In an elastic collision (a) the initial kinetic energy is equal to the final kinetic energy
(a) the initial kinetic energy is equal to the final kinetic energy Explanation: The initial kinetic energy before the collision and the final kinetic energy after the collision will remain the same....
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In an inelastic collsion (a) the initial kinetic energy is equal to the final kinetic energy
(b) the final kinetic energy is less than the initial kinetic energy Explanation: If the collision is perfectly inelastic the deformation of the bodies during the collision is permanent and the part of...
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