Two masses m and 2 m are dropped from heights h and 2h. On reaching the ground, which body will have a greater kinetic energy and why?

h1 = 1/ 2 gt21  h2 = 1/ 2 gt22 , as x = o  t1/ t2 = √(h1/h2) Ratio will not change in either case because acceleration remains the same. In case of...

Expression for kinetic energy  Ek= ½ mv2  m = Mass of object  v = Velocity of the object in ms−1  Given that kinetic energy, Ek=25J  (i) If the velocity of an object is doubled, then...

m g h = m ×10 ×10 = 100m J.  Energy is reduced by 40% then the remaining energy is 60m J.  Therefore, 60 m = m ×10 × h′ or h′...

When a freely falling body eventually stops on reaching the ground, its kinetic energy gets converted into heat energy (as the body and ground become warm due to collision), sound...

(a) Kinetic energy of an object is defined as the energy possessed by a body by virtue of its motion.  It is given by, K.E = 1/2 mv2  No, the kinetic energy...

As K .E = 1/2 mv2 therefore,  K . E ∝ m  K . E ∝ v2  Therefore, the change in velocity of a body will cause greater change in kinetic energy.

Solution: H1 =10 m, v1 =? Loss of energy =40% H2 =? On striking the floor, K.E = P.E ½ mv12 = mg H1 V1 = ?(2gH1)= ?( 2x9.8x10) V1= ?196= 14 m/s As the body loses 40% of its energy, final...

True In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system. This is because in such collisions, there is always a loss...

(a) the initial kinetic energy is equal to the final kinetic energy  Explanation:  The initial kinetic energy before the collision and the final kinetic energy after the collision will remain the same....

(b) the final kinetic energy is less than the initial kinetic energy  Explanation:  If the collision is perfectly inelastic the deformation of the bodies during the collision is permanent and the part of...