(i) According to the equation of motion under gravity v2 − u2 = 2gs
Where,
u = Initial velocity of the ball
v = Final velocity of the ball
s = Height achieved by...
According to the equation of motion under gravity v2 − u2 = 2gs
Where,
u = Initial velocity of the stone = 40 m/s
v = Final velocity of the stone = 0...
Law of conservation of momentum is applicable to isolated system (no external force is applied). In this case, the change in velocity is due to the gravitational force of earth.
Solution:
H1 =10 m, v1 =?
Loss of energy =40% H2 =?
On striking the floor, K.E = P.E
½ mv12 = mg H1
V1 = ?(2gH1)= ?( 2x9.8x10)
V1= ?196= 14 m/s
As the body loses 40% of its energy, final...
The correct answer is
(c) vA = vB
Explanation:
The ball 'A' thrown vertically upward will return back to the initial point with the same thrown speed but its direction will be downwards....
