Take g=10 m/s^2
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A ball is thrown vertically upward. It has a speed of 10 m/s when it has reached 0.5h. What is 'h'?
Is value of h=5 m
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A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
(i) According to the equation of motion under gravity v2 − u2 = 2gs Where, u = Initial velocity of the ball v = Final velocity of the ball s = Height achieved by...
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A stone is thrown vertically upward with an initial velocity of 40 m/s
According to the equation of motion under gravity v2 − u2 = 2gs Where, u = Initial velocity of the stone = 40 m/s v = Final velocity of the stone = 0...
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A ball thrown up vertically returns to the thrower after 6 s. Find
(a) Time of ascent is equal to the time of descent. The ball takes a total of 6 s for its upward and downward journey. Hence, it has taken 3 s...
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When a ball is thrown vertically upwards, its velocity goes on decreasing
According to the law of conservation, energy can neither be created nor be destroyed but can transform from one form to another. Therefore, K.E. Lost by the ball = P.E. gained...
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Suppose a ball of mass m is thrown vertically upward with an initial speed v, its speed decreases continuously till it becomes zero.
Law of conservation of momentum is applicable to isolated system (no external force is applied). In this case, the change in velocity is due to the gravitational force of earth.
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A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is, (a) u/g (b) u2 /2g (c) u2 /g (d) u/2g
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is, (b) u2 /2g
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A ball is dropped from a height of 10m. If the energy of the ball reduces by 40percent after striking ground, how high ball bounce
Solution: H1 =10 m, v1 =? Loss of energy =40% H2 =? On striking the floor, K.E = P.E ½ mv12 = mg H1 V1 = ?(2gH1)= ?( 2x9.8x10) V1= ?196= 14 m/s As the body loses 40% of its energy, final...
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A vector A points vertically upward and B points towards north. The vector product A x B is
(a) along west
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A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically ,
The correct answer is (c) vA = vB Explanation: The ball 'A' thrown vertically upward will return back to the initial point with the same thrown speed but its direction will be downwards....
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