- Both I and IV
- Both II and III
- Only I
- Only IV
Option 1 : Both I and IV
5 men: P, Q, R, S and T and
5 women: J, K, L, M and N. Following conditions should be kept in mind.
(A) Minimum two women should be in the team.
(E) If K is selected, then M will also be selected.
Case - 1 |
Case - 2 |
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Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
K |
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K |
M |
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M |
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(D) R will not be in the same team as J.
Case - 1 |
Case - 2 |
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Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
K |
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K |
M |
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M |
J |
R |
J |
R |
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(C) T and Q will always be in the same team.
Case - 1 |
Case - 1(a) |
Case - 2 |
Case - 2(a) |
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Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
K |
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K |
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K |
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K |
M |
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M |
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M |
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M |
J |
R |
J |
R |
J |
R |
J |
R |
T |
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T |
T |
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T |
Q |
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Q |
Q |
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Q |
(B) S will not be in the same team with P.
Case - 1 gets eliminated.
And Case - 2(a) formed one team t.e. KMRTQ.
Case - 1(a) |
Case - 2 |
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Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
K |
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K |
M |
P/S |
P/S |
M |
J |
R |
J |
R |
P/S |
T |
T |
P/S |
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Q |
Q |
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So, required combinations is;
As, Minimum of two women should be in the team.
So, Case 1(a) gets elimeinted.
Case - 1(a) |
Case - 2 |
Case - 2(a)" |
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Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
Team - 1 |
Team - 2 |
K |
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N |
K |
L |
K |
M |
P/S |
P/S |
M |
P/S |
M |
J |
R |
J |
R |
J |
R |
S/P |
T |
T |
P/S |
T |
P/S |
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Q |
Q |
L |
Q |
N |
So; teams may be;
NPJTQ, KMRSL, NSJTQ, KMRPL, LPJTQ, KMRSN, LSJTQ, and KMRPN.
Hence, only two teams can be formed i.e NSJTQ, KMRTQ.
Hence, option (1) is the correct answer.