AhmedNazir

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Option 1 : Both I and IV

5 men: P, Q, R, S and T and

5 women: J, K, L, M and N. Following conditions should be kept in mind.

(A) Minimum two women should be in the team.

(E) If K is selected, then M will also be selected.

Case - 1

Case - 2

Team - 1

Team - 2

Team - 1

Team - 2

K

 

 

K

M

 

 

M

 

 

 

 

 

 

 

 

 

 

 

 

(D) R will not be in the same team as J.

Case - 1

Case - 2

Team - 1

Team - 2

Team - 1

Team - 2

K

 

 

K

M

 

 

M

J

R

J

R

 

 

 

 

 

 

 

 

(C) T and Q will always be in the same team.

Case - 1

Case - 1(a)

Case - 2

Case - 2(a)

Team - 1

Team - 2

Team - 1

Team - 2

Team - 1

Team - 2

Team - 1

Team - 2

K

 

K

 

 

K

 

K

M

 

M

 

 

M

 

M

J

R

J

R

J

R

J

R

T

 

 

T

T

 

 

T

Q

 

 

Q

Q

 

 

Q

(B) S will not be in the same team with P.

Case - 1  gets eliminated.

And Case - 2(a) formed one team t.e. KMRTQ.

Case - 1(a)

Case - 2

Team - 1

Team - 2

Team - 1

Team - 2

K

 

 

K

M

P/S

P/S

M

J

R

J

R

P/S

T

T

P/S

 

Q

Q

 

So, required combinations is;

As, Minimum of two women should be in the team.

So, Case 1(a) gets elimeinted.

Case - 1(a)

Case - 2

Case - 2(a)"

Team - 1

Team - 2

Team - 1

Team - 2

Team - 1

Team - 2

K

 

N

K

L

K

M

P/S

P/S

M

P/S

M

J

R

J

R

J

R

S/P

T

T

P/S

T

P/S

 

Q

Q

L

Q

N

So; teams may be;

NPJTQ, KMRSL, NSJTQ, KMRPL, LPJTQ, KMRSN, LSJTQ, and KMRPN.

Hence, only two teams can be formed i.e NSJTQ,  KMRTQ.

Hence, option (1) is the correct answer.

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