Ten years later, age of X will be equal to the present age of Y. Sum of Y's age 4 years later and X's age 3 years ago is 67. If Z is twice of the present age of X, then what will be Z's age (in years) after 5 years?

LohaHridoy
  1. 51
  2. 71
  3. 61
  4. 31

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Option 3 : 61

Let the present age of Y be ‘N’

Thus ten years later X’s age = N

Therefore, present age of X = (N – 10)

According to question,

Sum of Y's age 4 years later and X's age 3 years ago is 67

⇒ (N + 4) + { (N – 10) – 3} = 67

⇒ 2N – 9 = 67

⇒ N = 76/2

⇒ X = 38

Thus, Y’s present age = 38

X’s present age = 38 – 10 = 28

Given,

Z is twice of the present age of × ⇒ Z’s present age = 2 × 28 = 56

Therefore, Z’s age after 5 years = 56 + 5 = 61.
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