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Option 3 : 27
Let the present age of A be ‘x’
Thus, nine years later B’ s age = x
Therefore, present age of B = (x - 9)
According to question,
Sum of A's age 3 years later and B's age 4 years ago is 76
⇒ (x + 3) + {(x - 9) - 4} = 76
⇒ × = 43
Thus, A’ s present age = 43
B’ s present age = 43 - 9 = 34
Given,
The age of C is half of the present age of B ⇒ C’ s present age = 17
Therefore, C’ s age after 10 years = 17 + 10 = 27.
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