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The total length of a runway is 1000 m. The elevation at distance 0,200 m, 400 m, 600 m, 800 m and 1000 m are 100.0 m, 99.2 m, 101.0 m, 101.8 m, 101.4 m and 101.0 m respectively. The effective gradient of runway will be.
A
0.10 %
B
0.26 %
C
0.43 %
D
0.65 %
Correct Answer:
0.26 %
Consider the following statements regarding ICAO recommendation for correction to basic runway length of these statements
1. The basic runway length should be increased at the rate of 7 percent per 300 m rise in elevation above the mean sea level.
2. The basic runway length after having been corrected for elevation should be further increased at the rate of 1 percent for every 1°C rise in airport reference temperature above the standard atmospheric temperature at that elevation.
3. The runway length after having been corrected for elevation and temperature should be further increased at the rate of 20% for every 1 percent of effective gradient.
A
1 and 2 are correct
B
2 and 3 are correct
C
1 and 3 are correct
D
1, 2 and 3 are correct
The runway length after correcting for elevation and temperature is 2845 m. If the effective gradient on runway is 0.5 percent then the revised runway length will be
A
2845 m
B
2910 m
C
3030 m
D
3130 m
The length of runway under standard conditions is 2000 m. The elevation of airport site is 300 m. Its reference temperature is 33.05°C. If the runway is to be constructed with an effective gradient of 0.25 percent, the corrected runway length will be
A
2500 m
B
2600 m
C
2700 m
D
2800 m
Total correction for elevation, temperature and gradient for a runway should not be more than
A
15 %
B
20 %
C
25 %
D
35 %
The length of a runway under standard atmospheric conditions is 1800 m. If the actual reduced level of the site is 1200 m, the design length of the runway is
A
2360 m
B
2460 m
C
2560 m
D
2660 m
The reduced level of the proposed site of an air port is 2500 m above M.S.L. If the recommended length by I.C.A.O. for the runway at sea level is 2500 m, the required length of the runway is
A
2500 m
B
3725 m
C
3000 m
D
3250 m
Find the area by co-ordinate method if the independent co-ordinates are (400, 400), (423, 456), (478, 498), (400, 400)
A
1510 cu. m
B
1150 cu. m
C
5110 cu. m
D
115 cu. m
A train passes two bridges of length 800 m and 400 m in 100 seconds and 60 seconds respectively. The length of the train is:
A
80m
B
90m
C
200m
D
150m
A man travels 600 km by train at 80 km/hr, 800 km by ship at 40 km/hr, 500 km by aeroplane at 400 km/hr and 100 km by car at 50 km/hr. What is the average speed for the entire distance :
A
$${\text{60 km/hr}}$$
B
$$60\frac{5}{123}{\text{ km/hr}}$$
C
$${\text{62 km/hr}}$$
D
$$65\frac{5}{123}{\text{ km/hr}}$$
Select the correct differences between char and varchar data types? i. varchar is non unicode and char is unicode character data type ii. char is ‘n’ bytes whereas varchar is actual length in bytes of data entered in terms of storage size iii. varchar is variable in length and char is the fixed length string iv. For varchar, if a string is less than the maximum length then it is stored in verbatim without any extra characters while for char if a string is less than the set length it is padded with extra characters to equalize its length to given length
A
i, iii, iv
B
ii, iii, iv
C
i, ii, iv
D
iii, iv