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A tank with capacity T liters is empty. If water flows into the tank from pipe X at the rate of x liters per minute and water is pumped out by Y at the rate of y liters per minute and x > y, then how many minutes will the tank be filled?

Correct Answer: $$\frac{{\text{T}}}{{{\text{x}} - {\text{y}}}}$$  minutes
Net volume filled in 1 minute
= (x - y) liters
∴ The tank will be filled in
= $$\frac{{\text{T}}}{{\left( {x - y} \right)}}$$  minutes

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