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A water tank with 64-gallon capacity is filled by pipe A and emptied by pipe B. If the rate of water flow through pipe A is 2 gallons per hour, how many gallons per hour should flow through pipe B so that when both pipes are open, the initially empty tank shold be full in exactly 96 hours?

Correct Answer: 4/3
Let, x gallons per hour should flow through pipe B In 1 hour A flouss 2 gallons ∴,, 96 hour A ,, (96 × 2) ,, = 192 ,, So 192 – 96x = 64 ⇒ x  =   192  -  64 96  =  43

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