Find the largest number which divides 397, 612 and 1300 to leave same remainder in each case.

Correct Answer: 43
The largest number which divides a, b and c to leave same remainder in each case = HCF (a-b, b-c, c-a). Therefore, the largest number which divides 399, 751 and 924 to leave same remainder in each case = HCF (612-397, 1300-612, 1300-397) = HCF (215, 688, 903) = 43.