A dryer is used for drying pears which has initial moisture content of 70 % (wet basis) and final moisture content of 5 % (wet basis). An experimental drying curve for the product indicates that the critical moisture content is 25 % (wet basis) and the time for constant drying is 5 min. Can you estimate the total drying time for product?

Correct Answer: 6.54 min
Initial product moisture content (Wo) = 0.7 / 0.3 = 2.33 kg (water) / kg (solids) Critical moisture content (Wc) = 0.25 / 0.75 = 0.333 kg (water) / kg (solids) Final moisture content (Wf) = 0.05 / 0.95 = 0.0526 kg (water) / kg (solids) Time for constant rate drying (tc) = 5 min Required Total drying time (Rc) = ((Wo) – (Wc)) / tc = (2.33 – 0.33) / 5 min = 0.4 kg (water) / kg (solids) min Falling rate drying time (tF) = (Wc)/Rc * ln ((Wc)/w) = 0.333/0.4 * ln (0.333 / 0.0526) = 1.54 min Total drying time (t) = 5 + 1.54 = 6.54 min