Which of the following is a correct method to find the fraction of unbound drug in plasma? Given where Cu is the concentration of unbound drug and C is total plasma drug concentration.

What will be the fraction of unbound drug if the unbound drug concentration is 0.99 g/ml and total plasma concentration is 160 g/ml?

A

0.006

B

1.61

C

0.618

D

0.010

What will be the unbound drug concentration if the unbound drug fraction is 0.52 and the total plasma concentration is 140 g/ml?

A

80 g/ml

B

82.8 g/ml

C

70 g/ml

D

72.8 g/ml

In a graph of rate of excretion versus plasma drug concentration, which kind of drug will give the below shown curve? (x axis- rate of excretion, y axis – plasma drug concentration)

A

Drug excreted only by filtration

B

Drug filtered and actively reabsorbed

C

Drug filtered as well as actively secreted

D

Drug reabsorbed actively

Which one is the correct equation to calculate the fraction of unbound drug in plasma?

A

Concentration of unbound drug in plasma / total plasma concentration of drug

B

Total plasma concentration of drug / Concentration of unbound drug in plasma

C

1/Concentration of unbound drug in plasma

D

1/total plasma concentration of drug

For a certain drug, the bile flow rate is 0.7 ml/mm, the biliary drug concentration is 2g/ml and the plasma drug concentration is 0.8g/ml. What will be the bile clearance?

A

1.50 ml/mm

B

1.75 ml/mm

C

2.75 ml/mm

D

3 ml/mm

To have a plasma distribution value of 900 ml and plasma drug concentration to be 1.2 mg/ml what should be the amount of drug that should be given to the patient?

A

1080 ml

B

1080 g

C

1080 mg

D

1g/ml

If the numerator of a fraction is increased by 150% and the denominator of a fraction increased by 200% fraction becomes 10/19. Find the fraction.

A

12/17

B

10/16

C

12/19

D

9/11

If the numerator of a fraction is increased by 2 and the denominator is increased by 3, the fraction becomes $$\frac{7}{9}$$ and if both the numerator as well as he denominator are decreased by 1, the fraction becomes $$\frac{4}{5}$$. What is the original fraction ?

A

$$\frac{5}{6}$$

B

$$\frac{9}{11}$$

C

$$\frac{13}{16}$$

D

$$\frac{17}{21}$$

If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?

A

31\/25

B

15\/17

C

14\/25

D

11\/16

The numerator and denominator of a fraction are in the ratio 3 : 4. If 9 is subtracted from the numerator, the resulting fraction in $$\frac{2}{3}$$ of the original fraction. The numerator of the original fraction is

A

27

B

18

C

36

D

9