Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

Velocity of the steam leaving the nozzle is 1200 m/s. The nozzle angle is 20° and the mean blade velocity is 500 m/s. The inlet and outlet angles of blades are equal. The mass of the steam flowing through the turbine per second is 0.4 kg. Considering the blades to be frictionless determine the Power Developed.

Correct Answer: 251.30 kW
Cbl = 500 m/s, C1 = 1200 m/s, α = 20°, ṁ = 0.4 kg/sec, θ = Ф Steps of Construction – Select a suitable scale and draw a line LM to represent Cbl (=500 m/s). At point M make angle of 20° (α) and cut length MS to represent the velocity 1200 m/s. Produce L to meet the perpendicular drawn from S at P. Thus inlet triangle is completed. By measurement: θ = 33°, Cr1 = 749.91 m/s θ = Ф = 33° Cr2 = Cr1 = 749.91 m/s At point L, make an angle of 33° (Ф) and cut the length LN to represent Cr2(= 749.91 m/s). Join MN. Produce M to meet the perpendicular drawn from N at Q. Thus outlet triangle is completed. By measurement: Cw1 = 1127.6 m/s and Cw2 = 128.9 m/s Power Developed = ṁ (Cw1 + Cw2) Cbl = 0.4(1127.6 + 128.9)500 = 251300 W or 251.3 kW

Steam issues from the nozzle with a velocity of 1000 m/s in a De Laval turbine. The nozzle angle is 20°, mean blade velocity is 350 m/s. The inlet and outlet angles of the blades are equal. The mass of the steam flowing through the turbine per second is 0.3 kg. Calculate the tangential force on the blades. Take blade velocity coefficient as 0.8.

In a single row impulse turbine, the absolute velocity of steam leaving the turbine is 900 m/s. The nozzle angel is 20°. The mean blade speed is 300 m/s. The inlet blade angle is equal to the outlet blade angle. Determine the angle made by the discharging steam with the tangent of the wheel at the exit of moving blade. Neglect friction on turbine blades.

In a De laval turbine, steam leaves nozzle with a velocity of 1300 m/s. The nozzle angle is 25° and the mean blade speed is 500 m/s. The inlet and outlet blade angles are equal. Find out work done per kg of steam if the blades of the turbine are frictionless.

In a Parson’s reaction turbine, the outlet angle of blade is 25°. Calculate the work done per second by the blades if the blade mean blade speed is 60 m/s and the absolute velocity of the steam leaving the nozzle is 120 m/s. The mass flow rate of steam is 0.1 kg per second.

A simple impulse turbine has a mean blade speed of 250 m/s. The nozzle angle is 20° and the steam velocity from the nozzle is 600 m/s. The turbine uses 3000 kg/h of steam. The blade outlet angle is 25°. Determine the amount of energy converted to heat by blade friction if the blade friction factor is 0.86.

In a single row impulse turbine, steam leaves the nozzle at 600 m/s. The nozzle angle and the mean blade speed is 25° and 200 m/s. The blade velocity coefficient is 0.8. Determine the blade outlet angle if the steam leaves the turbine blades axially.

In a reaction turbine, the fixed blades and the moving blades are of the same shape but reversed in direction. The mean blade speed is 30 m/s. The absolute velocity of the steam leaving the nozzle is 90 m/s and the absolute velocity of steam leaving the moving blade is 64 m/s. Determine the nozzle angle.

In a reaction turbine, the fixed blades and moving blades are of the same shape but reversed in direction. The angle of the discharging tip is 20°. The mean blade velocity is 200 m/s. The axial velocity of flow of steam is half of the mean blade velocity. Determine the inlet angles of blades.

In a single stage impulse turbine nozzle angle is 20° and the mean blade speed is 300 m/s. Steam leaves the nozzle at a velocity of 700 m/s. Determine the exit velocity of the steam if the turbine blades are equiangular and frictionless.

The following data refers to a particular stage of a Parson’s reaction turbine: Mean blade speed = 90 m/s Velocity of steam leaving the nozzle = 120 m/s Nozzle angle = 20° Mass flow rate of steam = 0.8 kg per second Calculate the tangential force on the blade.