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A single phase full bridge inverter circuit, has load R = 2 Ω and dc source Vs = 230 V. Find the value of power delivered to the load in watts only due to the fundamental component of the load current.

Correct Answer: 21424.5 W
The fundamental component of voltage = (4Vs/π) sinωt Peak value Vm = 4Vs/π Rms voltage = 4Vs/π√2 = 207 V RMS Current (Irms) = 207/2 = 103.5 A P = (Irms)2 x R = 21424.5 W.

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