A single-phase bridge inverter, fed from a 230 V dc is connected to the load R = 10 Ω and L = 0.03 H. Determine the fundamental component of rms output current. Fundamental output frequency of the square wave output = 50 Hz.
Correct Answer: 15 A
Vo1 (rms fundamental voltage) = 4Vs/π√2 = 207.10 V. Now, the load impedance at the fundamental frequency i.e. at 50 Hz will be Z1 = 1/2 = 13.7414 Ω Hence, I = V1/Z1 = (207.10)/(13.7414) = 15.07 A.