In AES, to make the s-box, we apply the transformation – b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci What is ci in this transformation?

Correct Answer: ci is the ith bit of byte c with value 0x63
ci is the ith bit of byte c with value 0x63 i.e, c = 01100011