In AES, to make the s-box, we apply the transformation b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i What is c_i in this transformation?

Correct Answer: c_i is the ith bit of byte c with value 0x63
Ci is the ith bit of byte c with value 0x63 i.e, c = 01100011.