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If in an alternating current circuit, capacitance C is connected to a supply of 200V,50Hz. Current in the circuit is 1.89 A. Find the capacitance C.

Correct Answer: 30 µF
XC= V/I = 200/1.89 = 106.1 Ω. XC=1/(2πfC) Substituting the values we get C = 30 µF.

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