A metal wire of linear mass density of 9.8/gm is stretched with a tension of 10kg wt between two rigid supports 1m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance, when carrying an alternating current of frequency v. The frequency v of the alternating source is?

Correct Answer: 50 Hz
Here, m=9.8/gm=9.8×10-3 kg/m T=10kg wt = 9.8×10=98N L=1m The fundamental frequency of vibration of the string, v=1/2L×√(T/m)=1/2×√(9.8/(9.8×10-3))=50Hz.