A short bar magnet of magnetic moment `20Am^(2)` has a cross sectional area of `1.5xx10^(-4)m^(2)`. If the intensity of magnetisation of the magnet is `10^(5)A//m`. The length of magnet is
A. `0.33m`
B. `0.13cm`
C. `1.33m`
D. `1.33cm`
i. The bar magnet said to have pole strength +qm and -qm near the north and south poles respectively.
ii. As bar magnet has two poles with equal and opposite pole strength, it is...
Given: m = 5.0 Am2, 2l = 20 cm = 0.20 m
To find: Pole strength (qm)
Formula: qm = \(\frac{m}{2l}\)
Calculation:
From formula.
qm = \(\frac{5.0}{0.20}\) = 25 Am
Given: m = 3.6 Am2, qm = 10.8 Am
To find:
i. Magnetic length
ii. Geometric length
Formulae:
i. Magnetic length = \(\frac{m}{q_m}\)
ii. Geometric length = \(\frac{6}{5}\) × magnetic length.
Calculation: From formula (i),
Magnetic length = \(\frac{3.6}{10.8}\) = 0.33 m
From formula (ii),
Geometric length...
Given: m = 0.48 JT-1, r = 10 cm = 0.1 m
To find:
i. Magnetic induction along axis (Ba)
ii. Magnetic induction along equator (Beq)
Formulae:
i. Ba = \(\frac{\mu_0}{4\pi}\,\frac{2m}{r^3}\)
ii. Ba = 2 Beq
Calculation: From formula (i),
Ba = 10-7 × \(\frac{2\times0.48}{10^{-3}}\)
∴...
When bar magnet is cut into two equal parts, then magnetic moment of each part becomes half of the original directed from S to N pole.
∴ Magnetic moment of the combination...