A conducting loop of cross-area `A` and resistance `R` is placed perpendicular to a magnetic field `B` . The loop is withdrawn completely from the fie

Question

A conducting loop of cross-area `A` and resistance `R` is placed perpendicular to a magnetic field `B` . The loop is withdrawn completely from the fie

A conducting loop of cross-area `A` and resistance `R` is placed perpendicular to a magnetic field `B` . The loop is withdrawn completely from the field. The change, which flows through any cross-section of the wire in the process
A. `(B)/(R)`
B. `(BA)/(R)`
C. `(B)/(2R)`
D. `(2B)/(R)`

Share with your friends

Talk Doctor Online in Bissoy App

Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Salim Ahmed Kawsar

Answered Feb 05, 2023

Call

Correct Answer - B
`Deltaq=(Deltaphi)/(R)=(BA)/(R)`

A conducting loop of cross-area `A` and resistance `R` is placed perpendicular to a magnetic field `B` . The loop is withdrawn completely from the fie

1 Answers