A proton takes `10^(-12)s` to complete one revolution in uniform magnetic field. The time taken in another orbit of double the radius in the same field is
A. `0.5xx10^(-12)sec`
B. `2xx10^(-12)sec`
C. `4xx10^(-12)sec`
D. `10^(-12)sec`


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Correct Answer - 4
`(T_(1))/(T_(2))=(m_(1))/(m_(2))xx(q_(2))/(q_(1))`

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