A black body radiates energy at the rate of `E "watt"//m^(2)` at a high temperature `TK` when the temperature is reduced to `[(T)/(2)]K` Then radiant

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A black body radiates energy at the rate of `E "watt"//m^(2)` at a high temperature `TK` when the temperature is reduced to `[(T)/(2)]K` Then radiant

A black body radiates energy at the rate of `E "watt"//m^(2)` at a high temperature `TK` when the temperature is reduced to `[(T)/(2)]K` Then radiant energy is .

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

Correct Answer - D
`E=sigmaT^(4)rArr(E_(1))/(E_(2))=((T_(1))/(T_(2)))^(4)`

A black body radiates energy at the rate of `E "watt"//m^(2)` at a high temperature `TK` when the temperature is reduced to `[(T)/(2)]K` Then radiant

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