0.5 g of bleaching powder was suspended in water an excess of KI added. On acidifying with dilute `H_(2)SO_(4)` iodine was liberated which required 50 mL of `N//10` hypo solution. Calculate the percentage of available chlorine in bleaching powder.
1 Answers
Talk Doctor Online in Bissoy App
Why does moist Cl2 act as bleaching agent ? A) In presence of water, Cl2 gives nascent hydrogen.
B) In presence of water, Cl2 gives nascent oxygen.
2 Answers 1 views
When dilute hydrochloric acid is added to iron filings
A) hydrogen gas and iron chloride are formed
2 Answers 1 views
Ritwik added some yeast powder to sugar solution and kept it for a day. The next day he will observe that
(D) The solution smells like alcohol and bubbles are seen on top
2 Answers 1 views
Iron powder and powder of rust are taken in two containers X and Y respectively. Dilute sulphuric acid is added two containers
Correct Answer - B Iron is an element and rust is a compound of iron in which iron does not retain its properties and hence rust does not liberate hydrogen gas...
2 Answers 1 views
Statement `SO_(2)` can be used as reductant as well as oxidant. Explanation The oxidation number of `S` in `+4` in `SO_(2)` which lies between its min
Correct Answer - C `-do-`
2 Answers 1 views
Statement `109 % H_(2)SO_(4)` represent a way to express concentration of industrial `H_(2)SO_(4)`. Explanation It represents that `9 g H_(2)O` reacts
Correct Answer - D Both are facts
2 Answers 1 views
Assertion::In the electrolysis of water containing 15 to 20 percent `H_(2)SO_(4) SO_(4)^(2-)` ions are not discharged at anode. Reason: The discharge
(a) Reason is the correct explanation for assertion.
2 Answers 1 views
When `AgNO_(3)(aq)` reacts with excess of iodine, we get:
Correct Answer - B `5AgNO_(3)+3I_(3)("excess")+3H_(2)OtoHIO_(3)+5Agl+5HNO_(3)`.
2 Answers 1 views
$ Acidified `K_(2)Cr_(2)O_(7)` is turned green when `SO_(2)` is passed thorugh it. ! In this reaction `SO_(2)` acts as a reducing agent.
Both assertion (A) and reason (R) are correct and R is the correct explanation of A.
2 Answers 1 views
An aqueous solution of `FeSO_(4),Al_(2)(SO_(4))_(3)` and chrome alum is heated with excess of `Na_(2)O_(3)` and filtered. The material obtained are `:
Correct Answer - C (c ) TIPS`//` FORMULAE`:` Chrome alum is `K_(2)SO_(4).Cr_(2)(SO_(4))_(3).24H_(2)O`. The filtrate is yellow due to `CrO_(4)^(2-)` ion and residue is brown due to `Fe(OH)_(3)`.
2 Answers 1 views