If the wave number of the first line in the Balmer series of hydrogen atom is `1500cm^(-1)`, the wave number of the first line of the Balmer series of

Kuch bhi

Correct option is A) valency

Correct option is D) m2 x2

Correct option is A) \(^{16}_8O\)

\(\frac1{\lambda}=R(\frac1{n_1^2}-\frac1{n_2^2})\) R → Rydburg constant Balmer series n1 = 2 n2 = \(\infty\) for highest energy n2 → \(\infty\)  \(\frac1{\lambda_B}=R(\frac1{2^2}-\frac1{\infty})\)  \(\frac1{\lambda_B}=R(\frac1{4})\)  \(\frac1{\lambda_B}=R(\frac R{4})\)  \({\lambda_B}=\frac4{R}\)  for paschen series n1 = 3, n2 = \(\infty\) \(\frac1{\lambda_p}=R(\frac{1}{(3^2)}-\frac1{(\infty^2)})\)  \(\frac1{\lambda_p}=\frac{R}{p}\)  \(\lambda_p=\frac{q}R,\)   \(\frac{\lambda_b}{\lambda_p}=\cfrac{\frac4R}{\frac{q}R}\)  ⇒  \(\frac4R\times\frac{R}q\) ⇒ 4 : q

(A) 1 – b, 2 – c 3 – a

Answer is (D) F ∝ \(\frac{1}{n^4}\)

Correct Answer - A `bar(v) = (1)/(lambda) = R [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`

Correct Answer - a,b,c