When a multidimensional array is accessed, each array index is ...........
(a) Separated by column.
(b) Surrounded by brackets and separated by commas.
(c) Separated by commas and surrounded by brackets.
(d) Surrounded by brackets,
Answered Feb 05, 2023
(d) surrounded by brackets
A) both x and y are true
Correct option is D) 8/9
Correct option is C) 4/6
A = \(\begin{bmatrix}8&-8&-2\\4&-3&-2\\3&-4&1\end{bmatrix}\) A2 = \(\begin{bmatrix}8&-8&-2\\4&-3&-2\\3&-4&1\end{bmatrix}\)\(\begin{bmatrix}8&-8&-2\\4&-3&-2\\3&-4&1\end{bmatrix}\) = \(\begin{bmatrix}26&-32&-2\\14&-15&-4\\11&-16&3\end{bmatrix}\) A4 = A2. A2 = \(\begin{bmatrix}26&-32&-2\\14&-15&-4\\11&-16&3\end{bmatrix}\)\(\begin{bmatrix}26&-32&-2\\14&-15&-4\\11&-16&3\end{bmatrix}\) = \(\begin{bmatrix}206&-320&-70\\110&-159&20\\95&-160&51\end{bmatrix}\)
We have A = IA \(\begin{bmatrix}2&1&1\\3&2&1\\2&1&2\end{bmatrix}=\) \(\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}\)A Applying R3 → R3 — R1 R2 → 2R2 — 3R1 \(\begin{bmatrix}2&1&1\\0&1&-1\\0&0&1\end{bmatrix}=\)\(\begin{bmatrix}1&0&0\\-3&2&0\\-1&0&1\end{bmatrix}\)A Applying R2 → R2 + R3 \(\begin{bmatrix}2&1&1\\0&1&0\\0&0&1\end{bmatrix}=\)\(\begin{bmatrix}1&0&0\\-4&2&1\\-1&0&1\end{bmatrix}\)A Applying R1 → R1 — R2 — R3 \(\begin{bmatrix}2&0&0\\0&1&0\\0&0&1\end{bmatrix}=\) \(\begin{bmatrix}6&-2&-2\\-4&2&1\\-1&0&1\end{bmatrix}\)A Applying R1 → \(\frac{R_1}2\) \(\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}=\)\(\begin{bmatrix}3&-1&-1\\-4&2&1\\-1&0&1\end{bmatrix}\)A Hence A-1 = \(\begin{bmatrix}3&-1&-1\\-4&2&1\\-1&0&1\end{bmatrix}\)
this is the solution!!!!
Is there any answer
(d) All of Above
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