0. 023 lies between (A) 0.2 and 0.3 (B) 0.02 and 0.03 (C) 0.03 and 0.029 (D) 0.026 and 0.024

Correct option is: (B) normal force

Correct option is  D) infinity

Correct option is (D) \(\frac{a+b}{2}\) \(\frac{a+b}{2}\) is a rational number lying between two rational numbers a and b.

Correct option is (C) 5/2 (A) \(\frac{2}{3}\) = \(0.\bar6\) < 2, (B) \(\frac{3}{2}\) = 1.5 < 2, (C) \(\frac{5}{2}\) = 2.5 lies between 2 and 3, (D) \(\frac{5}{3}\) = \(1.\bar6\) < 2

Correct option is (D) Q3 \(\because\) \((x_1,y_1)\) lies in \(Q_2\) \(\therefore\) \(x_1<0\) & \(y_1>0\) Also given that \((x_2,y_2)\) lies in \(Q_3.\) \(\therefore\) \(x_2<0\), \(y_2<0\) \(\because\) \(x_1<0\) & \(y_2<0\) \(\therefore\) \((x_1,y_2)\) lies in \(Q_3\)

(D) z lies on a circle |z – zi | = |z| |1 – i| = 1 \(\therefore\) |z| = 1/√2 \(\therefore\) x2 + y2 = 1/2

Correct Answer - C `-do-`

Correct Answer - A::C::D Clearly `R(alpha,beta)` is centroid of `DeltaABC`s `:.R(alpha,beta)=((3+1+2)/3,(9+2+3)/3)=(2,14/3)` `impliesalpha=2` and `beta=14/3` Hence `2alpha+3beta=18`