Find the vector joining the points P(2, 3, 0) and Q(– 1, – 2, – 4) directed from P to Q.
Answered Feb 05, 2023
Given P(2,3,0) and Q (-1,-2,-4) P (2,3,0) Q (-1,-2,-4) PQ =(−1−2)i+(−2−3)j+(−4−0)k =−3i−5j−4k ∴ Vector jonining P and Q given by PQ =−3i−5j−4k.
A) magnitude, direction
Correct option is D) rectangle
As the electric field vector \((\overrightarrow{E}_0)\) is more prominent than the magnetic field vector \((\overrightarrow{B}_0)\), it is responsible for optical effects due to EM waves. For this reason, electric vector is called light vector.
Resultant vector \(\vec p\times\vec q\)\(=\begin{vmatrix}\hat i&\hat j&\hat k\\3&-5&7\\2&5&-5\end{vmatrix}\) = \(\hat i(25-35)-\hat j(-15-14)+\hat k(15+10)\) = -10\(\hat i\) + 29\(\hat j\) + 25\(\hat k\) vector of magnitude 10 and parallel to resultant vector is \(\vec n=\frac{\pm10(-10\hat i+29\hat i+25\hat k)}{1-10\hat i+29\hat...
Correct option is B) rectangle
Correct option is C) 15 cm
The correct answer is (D) gizzard
Some one please give this answer
Correct Answer - A we have , ` veca.vecb= veca.vecc = vec0` ` Rightarrow veca bot vecb, veca bot vecc` ` Rightarrow veca || (vecb xx vecc)` ` Rightarrow veca...
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