Find the sum of all numbers between 200 and 300 which when divided by 7 leaves remainder 1. [Class 11 Maths]

\(\frac{60002-601}6=\frac{59401}6=9900\times6+\frac16\) Hence, the required remainder is 1.

Please tell if my answer is correct or not.

Correct Answer - 1,-1,2

We know that if a number is divided by 5, then remainder is remainder obtained by dividing unit place by 5.  ∴ Here, 7 ÷ 5 gives 2 as a remainder.  Hence,  remainder...

Let the numbers be ‘a’ and ‘b’.  Given, sum of two numbers is 8 and 15 times the sum of their reciprocals is also 8.  ⇒ a + b = 8  ⇒ a...

Let the numbers be ‘a’ and ‘b’  Given, sum of two numbers is 18. The sum of their reciprocals is 1/4  ⇒ a + b = 18  ⇒ b = 18 – a  Also,...

All odd numbers between 0 and 50 are 1, 3, 5, 7,……… 49. This is an AP in which a = 1, d = (3 - 1) = 2 and \(l=49.\) Let the...

Correct Answer - D Use remainder theorem.