The cost of 5(2/5) litres of milk is ₹ 101(1/4) then find the cost of 1 litre.

(D) law of gaseous volumes \(\underset{2L}{H_2(g)}+\underset{2L}{O_2(g)}\longrightarrow \underset{2L}{H_2O(g)}\) Gay-Lussac's states that "At same temperature and pressure, when gases combine or produced in a chemical reaction, they do so in a simple ratio by volume. Here, \(H_2\), \(O_2\) and \(H_2O(g)\) are...

Correct Answer - 553 km

Correct option is (B) 100 Let p(x) = \(x^{101}+101\) \(\because\) When p(x) is divided by (x+1), it leaves remainder p(-1). Now, p(-1) = \((-1)^{101}+101\) = -1+101 = 100 Hence, the remainder when \(x^{101}+101\) is divided by \((x+1)\) is 100.

Correct option is (D) Rs \(18\frac{3}{4}\) \(\because\) Cost of \(5\frac{2}{5}\) litres of milk = Rs \(101\frac{1}{4}\)  \(\Rightarrow\) Cost of \(\frac{27}{5}\) litres of milk = Rs \(\frac{405}4\) \(\therefore\) Cost of 1 litres of milk = Rs \((\frac{405}4\div\frac{27}5)\) = Rs \((\frac{405}4\times\frac5{27})\) = Rs \((\frac{45}4\times\frac5{3})\) = Rs \((\frac{15\times5}4)\) = Rs \(\frac{75}4\) = Rs \(\frac{18\times4+3}4\) = Rs \((18+\frac34)\) = Rs \(18\frac{3}{4}\).

C) both ‘A’ and ‘B’

Correct option is (B) ₹ 176 \(\because\) The cost of 5 litres of petrol = Rs 110. \(\therefore\) The cost of 8 litres of petrol \(=Rs\,(\frac{110}5\times8)\) \(=Rs\,(22\times8)\) = Rs 176

Let the cost of 1 pen be ‘a’ and the cost of 1 pencil be ‘b’. Given, 5 pens and 6 pencils together cost Rs 9. 5a + 6b = 9 --------- (1) Given, 3...

Correct Answer - B `W=-2.303 nRT "log" V_(2)/V_(1)`