let length of the rectangle be L and breadth be B
so by the problem perimeter 2(IL+B)=34
=> L+B =17 .......(1)
=> L2+B2+2LB=289 ..........(2)
and the square of the diagonal = L2+B2=132 =169 .....(.3)
By...
Correct option is (C) 4 (x + y – z)
Let side length of the square be a unit.
\(\therefore a^2=x^2+y^2+z^2+2xy-2yz-2zx\)
\(=x^2+y^2+(-z)^2+2\times x\times y\) \(+2\times y\times -z+2\times -z\times x\)
\(=(x+y-z)^2\) sq. units
\(\Rightarrow\) \(a=(x+y-z)\) unit
\(\therefore\) Perimeter of the square =...
Correct option is (C) 12√2
Let side of equilateral triangle is a cm.
Then \(\frac{\sqrt3}4a^2=8\sqrt3\) \((\because\) Area of equilateral triangle is \(\frac{\sqrt3}4a^2)\)
\(\therefore a^2=32\)
\(\Rightarrow a=\sqrt{16\times2}=4\sqrt2\)
\(\therefore\) Perimeter of equilateral triangle = 3a
\(=3\times4\sqrt2\) \(=12\sqrt2\,cm\)