If the radius and height of a cylinder is x cm and y cm respectively, then the curved surface area of cylinder. 

Correct Answer - (i) 1m (ii) `1.54 m^(3)`

Correct Answer - `269.5 cm^(3)`

Correct Answer - `1078 cm^(3)`

CSA (cone) = πrl = 12320 \(\frac{22}{7}\) × 56 × l = 12320 l = 70 cm h = \(\sqrt{70^2-56^2}\) = 42 cm

Correct option is (C) Decreased by 50% Let r and h be parameters of original cylinder & R and H be parameters of another cylinder. Let R = 2r Also \(2\pi RH=2\pi rh\)   ...

Correct option is (A) 77 cm2 r = 3.5 cm Curved surface area of hemispherical bowl \(=2\pi r^2\) \(=2\times\frac{22}7\times3.5\times3.5\) \(=22\times3.5\) \(=77\,cm^2\)