Which of the following points is at a distance of 6 units from Y – axis measured along positive X – axis ?
A) (8, 6)
B) (6, 8)
C) (0, 6)
D) (8, 2)
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Find the equation of a line parallel to the x-axis ata distance of (i) 4 units above it (ii) 5 units below it.
Correct Answer - (i)y-4=0 (ii)y+5=0
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Find the equation of a line parallel to the y-axis at a distance of (i)6 units to its right (ii) 3 units to its left.
Correct Answer - (i)x-6=0 (ii)x+3=0
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If the distance of a point from X-axis is 8 units and its distance from Y-axis is 3 units then the point is denoted by
Correct option is (D) (3, 8) The distance of point from Y-axis is x = 3 and the distance of point from X-axis is y = 8. \(\therefore\) Point is (3, 8).
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If the distance of a point from X-axis is 8 units and its distance from Y-axis is 3 units then the point is denoted by
2 Answers
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Which of the following points is at a distance of 6 units from Y – axis measured along positive X – axis ?
Correct option is (B) (6, 8) \(\because\) Points is at a distance of 6 units from Y–axis. \(\therefore\) x-coordinate of that point is 6. Among all given points only (6, 8) has x-coordinate 6.
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The point at a distance of 4 units from X-axis and 5 units from Y-axis is
Correct option is (A) (5, 4) x = Obscissa = Distance of point from Y-axis = 5, y = Ordinate = Distance of point from X-axis = 4. Thus, the point is (5, 4).
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The point in Q2 which is at a distance of 6 units from X-axis, 3 units from Y- axis is
Correct option is (C) (-3, 6) In \(Q_2\), x-coordinate is negative and y-coordinate is positive. \(\because\) Distance of point from Y-axis = 3 units \(\therefore\) Abscissa = -3 \((\because\) x-coordinate is negative) \(\because\) Distance of point from X-axis = 6 units \(\therefore\) Ordinate = 6 \(\therefore\) Required point...
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The point in Q2 which is at a distance of 6 units from X-axis, 3 units from Y- axis is
2 Answers
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Base of a coloured flag which is in the shape of triangle is 2 + √2 units and height is 2 – √2 units. Then the area of flag in square units.
Correct option is (C) 1 Area of flag \(=\frac12\times\) Base \(\times\) Height \(=\frac12\times(2+\sqrt2)\times(2-\sqrt2)\) \(=\frac{4-2}2\) = 1 square units
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