Simplify: (3x+2)(9x2-6xy+4y2)


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a3−b3=(a−b)(a2+ab+b2)

a3+b3=(a+b)(a2−ab+b2)

Given,

(3x+2y)(9x2−6xy+4y2)

=(3x)3+(2y)3

=27x3+8y3