How long can an electric lamp of 100 W be kept glowing by fusion of 2 kg of deuterium? Take the fusion reaction as

Monjur Alahi

How long can an electric lamp of 100 W be kept glowing by fusion of 2 kg of deuterium? Take the fusion reaction as

\(^2_1\)H + \(^2_1\)H → \(^3_2\)He + n + 3.27 MeV


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Salim Ahmed Kawsar

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Number of atoms present in 2 g of deuterium = 6 × 1023

Number of atoms present in 2.0 Kg of deuterium = 6 × 1026

Energy released in fusion of 2 deuterium atoms

= 3.27 MeV

Energy released in fusion of 2.0 Kg of deuterium atoms

= \(\frac{3.27}{2}\) × 6 × 1026 MeV

= 9.81 × 1026 MeV

= 9.81 × 1026 MeV

= 15.696 × 1013 J

Energy consumed by bulb per sec = 100 J

Time for which bulb will glow = \(\frac{15.696\times10^{13}}{100}\) s = 4.97 × 104 year

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