Assertion (A): Displacement is a vector. Reason (R) : Displacement has both magnitude and direction. 

Magnitude of torque, τ = r F sin θ where θ is the smaller angle between the directions of \(\overrightarrow{r}\) and \(\overrightarrow{F}\). Special cases: 1. If θ = 90°, τ = τmax = rF. Thus, the force should be applied along normal direction...

Correct Answer - `vec(r ) =(2hat(i) +hat(j) -5hat(k)) +lambda(hat(i) +3hat(j)-hat(k)) ,(x-2)/(1)=(y-1)/(3)=(z+5)/(-1)`

Given: m = 0.48 JT-1, r = 10 cm = 0.1 m To find: i. Magnetic induction along axis (Ba) ii. Magnetic induction along equator (Beq) Formulae: i. Ba = \(\frac{\mu_0}{4\pi}\,\frac{2m}{r^3}\) ii. Ba = 2 Beq Calculation: From formula (i), Ba = 10-7 × \(\frac{2\times0.48}{10^{-3}}\) ∴...

As the electric field vector \((\overrightarrow{E}_0)\) is more prominent than the magnetic field vector \((\overrightarrow{B}_0)\), it is responsible for optical effects due to EM waves. For this reason, electric vector is called light vector.

Resultant vector \(\vec p\times\vec q\)\(=\begin{vmatrix}\hat i&\hat j&\hat k\\3&-5&7\\2&5&-5\end{vmatrix}\) = \(\hat i(25-35)-\hat j(-15-14)+\hat k(15+10)\) = -10\(\hat i\) + 29\(\hat j\) + 25\(\hat k\)  vector of magnitude 10 and parallel to resultant vector is  \(\vec n=\frac{\pm10(-10\hat i+29\hat i+25\hat k)}{1-10\hat i+29\hat...

B) Only magnitude, no direction

C) A is true, but R is false

Some one please give this answer

Correct Answer - A Both, the assertion and reason are true and the latter is correct explanation of the former.