Radical form of 271/5 is
A) \(\sqrt{27}\)
B) \(\sqrt[3]{27}\)
C) \(\sqrt[4]{27}\)
D) \(\sqrt[5]{27}\)
Answered Feb 05, 2023
Correct option is (D) \(\sqrt[5]{27}\)
\(27^{\frac15}\) = \(\sqrt[5]{27}\)
Correct option is D) \(\sqrt[5]{27}\)
Correct option is (C) \(\sqrt[3]{225}\) \(15^\frac23=(15^2)^\frac13\) \(=(225)^\frac13=\sqrt[3]{225}\)
Correct option is (A) \(\sqrt[3]{36}\) \(6^\frac23=(6^2)^\frac13=(36)^\frac13\) = \(\sqrt[3]{36}\)
Correct option is (A) \(\sqrt[5]{3^1}\) \(3^\frac{1}{5}=\sqrt[5]{3}\) = \(\sqrt[5]{3^1}\)
Correct option is C) cation
Correct option is B) anion
Correct Answer - B This option is not characteristics of free radical chain reaction.
Install the Bissoy app to consult with a doctor.
Log in to ask questions, provide answers, or leave comments.
