Correct option is (A) 1/6
Possible outcomes are S = {1, 2, 3, 4, 5, 6}
\(\therefore\) n(S) = 6
Number which is a perfect square and a perfect cube is 1. \((\because1^3=1\;\&\;1^2=1)\)
Hence, favourable outcome...
Correct option is (C) 5
720 \(=9\times16\times5=3^2\times4^2\times5.\)
Since, factors 3 & 4 are in square but 5 is not in square.
\(\therefore\) We have to multiply 720 by 5 to get a perfect square number.
