Identify correct sentence given below:
A) Right kidney – slightly lower than left kidney
B) Right kidney – slightly higher than left kidney
C) Right kidney – left kidney are same height
D) Right kidney is nearer to vertebral column than left kidney
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____________ should state the topic of the paragraph in clear words. ( Closing sentence, Main body, Topic sentence, Middle sentence)
Main body should state the topic of the paragraph in clear words
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4. The value of \( \left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2} \) is (a) \( \frac{61}{144} \) (b) \( \frac{144}{61} \) (c) 29 (d) none of these
Correct answer is:- (c) 29 Explanation:- 1/2-2 + 1/3-2 + 1/4-2 = 22 + 32 + 42 (x-1 = 1/x) = 4 + 9 + 16 = 29
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Consider a particle of mass \( m \) having linear momentum \( P \) at position \( r \) relative to the origin \( O \). Which of the following equations correctly relates \( r , P , L \) ? a) \( \left[\left(\frac{d L}{d t}\right)+r x\left(\frac{d P}{d t}\right)\right]=0 \) b) \( \left[\left(\frac{d L}{d t}\right)-r x\left(\frac{d P}{d t}\right)\right]=0 \) c) \( \left[\left(\frac{d L}{d t}\right) \times\left(\frac{d r}{d t}\right) \times P\right]=0 \) d) \( \left[\left(\frac{d L}{d t}\right)-\left(\frac{d r}{d t}\right) \times P\right]=0 \)
Correct answer is (b) We know that \(\tau\) = r × F ∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\) \(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\) \(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
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a – Right kidney is slightly lower in position b – Right abdominal region of body is occupied by liver ‘
B) Both a & b are true, b doesn’t explain a
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The position of the right kidney is lower than the left kidney due to the :
D) Presence of liver above it
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The sum value of the series \( \sin p+x \sin (p+q)+ \) \( \left[\left(x^{2}\right) / 2 !\right] \sin (p+2 q)+\ldots \ldots . . \) is
Given series is sin(p + x) sin(p + q) + x2/2! sin(p + 2q) + .... We know that eiα = cos α + i sin α. We develop new series cos p + x cos(p +...
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(1.) If \( T={ }_{B}^{A}\left(\begin{array}{cc}0.25 & 0.75 \\ 0.3 & \alpha\end{array}\right) \) is a transition probability matrix, then the value of \( \alpha \) is a) \( 0.5 \) b) \( 0.7 \) c) 0 /d) \( 0.6 \) 2. Rank of matrix \( \left(\begin{array}{cccc}1 & -1 & 2 & 0 \\ 0 & 2 & 0 & 3\end{array}\right) \) is a) 1 b) 0 c) 2 d) \( -1 \)
Is there any answer
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H.C.F of \( \left(x^{2}-3 x+2\right) \) and \( \left(x^{2}-4 x+3\right) \)
x2 −3x+2=x 2 −2x−x+2 x(x−2)−1(x−2)=(x−2)(x−1) Now x2 −4x+3=x 2 −3x−x+3 x(x−3)−1(x−3)=(x−3)(x−1) Thus, the only common factor is (x-1)
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