A ray of light incident with 45° on one of the lateral surface of an equilateral prism placed on the horizontal surface of a table. Find the minimum deviation produced by a prism.
Given: m = 20 kg, FL = 100 N, μk = 0.4
To find:
i. Coefficient of static friction (μS)
ii. Minimum force required (Fk)
Formulae:
i. μs = \(\frac{F_L}{N}=\frac{F_L}{mg}\)
ii. μS = \(\frac{F_K}{N}\)
Calculation:
From formula (i),
μs = \(\frac{100}{20\times9.8}\) = 0.5102
From formula (ii),
Fk = μkN...
δ = 30°, A = 60°, μ = √2
Let us find the minimum value of angle of deviation δ that is δm
\(\boxed {µ = \frac {sin [\frac {A + δm}2]} {sin (\frac {A}{2})}} \) This...